(16x^2+64x+32)/352=0

Solution for (16x^2+64x+32)/352=0 equation:

(16x^2+64x+32)/352=0

We multiply all the terms by the denominator


(16x^2+64x+32)=0

We get rid of parentheses

16x^2+64x+32=0

a = 16; b = 64; c = +32;
Δ = b2-4ac
Δ = 642-4·16·32
Δ = 2048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2048}=\sqrt{1024*2}=\sqrt{1024}*\sqrt{2}=32\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-32\sqrt{2}}{2*16}=\frac{-64-32\sqrt{2}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+32\sqrt{2}}{2*16}=\frac{-64+32\sqrt{2}}{32}
$